
Author  Message 

anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Puzzles and Questions Fri Apr 23, 2010 9:05 pm  
 Post here all the nice puzzles you have and all the nice questions you have to baffle the other members.
Here is one from me:
This is just a mathematical puzzle, which would require some thinking. So, here it goes : (note each point carefully)
Two Mathematicians were travelling together. They both were neighbours and had been to each other's houses many times.
The first Mathematician tells the second one that he has three daughters. The second one is tottaly baffled, as he never knew about these three daughters of the first mathematician.
The first Mathematician tells the second one that the product of the ages of his three daughters is 36. The second Mathematician is asked to find out the ages of the first one's daughters. The second one replies saying that the data/ information given was not sufficient.
As the second clue, the First Mathematician tells the second that the sum of his three daughter's ages is numerically equal to his( the first mathematician's) house number. The second Mathematician is asked to find out the ages of the first one's daughters. He again says that the data/ information given was not sufficient.
As the third clue, the First Mathematician tells the second one that his youngest daughter is 2 feet 5 inches tall. The second Mathematicain is now able to guess their correct ages.
It is you now who is supposed to guess the answer the second scientist gives to the first scientist.
(P.S Any of the given clues can be irrelevant to the question and may be given just to confuse you.) 

 
Jammy Simply Sports Addict
Posts : 1549 Join date : 20100415 Age : 21 Location : Bury, England Birthday : 19951010
 Subject: Re: Puzzles and Questions Fri Apr 23, 2010 11:48 pm  
 There is a garden and some random guy decides to plant magical seeds within it. The seed packet suggests that everyday, the flowers will double their amount and after 30 days, the garden will be full. What day will the garden be half full? 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 8:50 am  
  Jammy wrote:
 There is a garden and some random guy decides to plant magical seeds within it. The seed packet suggests that everyday, the flowers will double their amount and after 30 days, the garden will be full. What day will the garden be half full?
The 29th day, because this is an example of geometric progression and not arithmetic progression.
Try my riddle. At least ponder over it for some while. 

 
Pav Administration
Posts : 4877 Join date : 20091205 Age : 24 Location : Australia Birthday : 19930315
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 9:01 am  
 I'll have a try at yours Anurag, you may need to give me about 10 years though _________________________________________________________________ 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 
 
Pav Administration
Posts : 4877 Join date : 20091205 Age : 24 Location : Australia Birthday : 19930315
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 9:24 am  
 Hehe, I haven't even read it yet, that's why I said I'll take 10 years as I will probably never ever be bothered reading it.... (It's a shocking habit)
I will read it now and I'll give ya an answer... _________________________________________________________________ 

 
Pav Administration
Posts : 4877 Join date : 20091205 Age : 24 Location : Australia Birthday : 19930315
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 9:34 am  
 ANSWER
Find the possible ways to multiply 3 and get 36. Here they are: 1  1  36 =38 1  2  18 = 21 1  3  12 =16 1  4  9 =14 1  6 – 6= 13 2  2  9 =13 2  3  6 =11
It would be reasonable to presume that we could come up with the above answers, it means that the house number must have been 13. If it was any of the other numbers, he could have figured out the answer from the start. As soon it mentioned the oldest daughter, 1  6  6 was out, as in that case there is no oldest daughter. Thus the answer, 2  2  9!
Tada! _________________________________________________________________ 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 9:41 am  
  Pav_001 wrote:
 ANSWER
Find the possible ways to multiply 3 and get 36. Here they are: 1  1  36 =38 1  2  18 = 21 1  3  12 =16 1  4  9 =14 1  6 – 6= 13 2  2  9 =13 2  3  6 =11
It would be reasonable to presume that we could come up with the above answers, it means that the house number must have been 13. If it was any of the other numbers, he could have figured out the answer from the start. As soon it mentioned the oldest daughter, 1  6  6 was out, as in that case there is no oldest daughter. Thus the answer, 2  2  9!
Tada!
Exceptional Pav. Too good. 166 is the answer though as i had mentioned the youngest daughter. 

 
Pav Administration
Posts : 4877 Join date : 20091205 Age : 24 Location : Australia Birthday : 19930315
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 9:56 am  
 Well I still win.. see what I mean about not reading things _________________________________________________________________ 

 
Jammy Simply Sports Addict
Posts : 1549 Join date : 20100415 Age : 21 Location : Bury, England Birthday : 19951010
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 3:15 pm  
 Pav is a genius Ha! I'm a dirty post whore.... 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 
 
Pav Administration
Posts : 4877 Join date : 20091205 Age : 24 Location : Australia Birthday : 19930315
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 6:10 pm  
 Haha, yeah Jammy And Jammy being completely honest, It was worked out all myself mate I'll put some up soon. _________________________________________________________________ 

 
Jammy Simply Sports Addict
Posts : 1549 Join date : 20100415 Age : 21 Location : Bury, England Birthday : 19951010
 Subject: Re: Puzzles and Questions Sat Apr 24, 2010 7:59 pm  
 I...I was set up 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Fri Apr 30, 2010 12:23 pm  
 Another mathematical puzzle from me ( Especially for pav "the genius")
Arrange 1000, $1 coins into 10 packets, such that you should be able to give me any integral (1, 2, 3...and not decimal numbers) quantity of money ranging from 11000, through only packets ( i.e. you cannot remove some coins from a packet and give it to me, but you have to give me the packet as a whole)
Like for eg:
If I have to distribute 10, 1$ coins into four packets, I would distribute it as follows : $1 in one packet. $2 in one packet. $3 in one packet. $4 in one packet.
Thus I can give you any quantity you ask for from 1$  10$
1$  1$ 2$  2$ 3$  3$ or 1$ + 2$ 4$  4$ or 1$ + 3$ 5$  1$ + 4$ or 2$ + 3$ 6$  2$ + 4$ 7$  3$ + 4$ or 1$ + 2$ + 4$ 8$  1$ + 3$ + 4$ 9$  2$ + 3$ + 4$ 10$1$ + 2$ + 3$ + 4$
P.S. You cannot use 1 packet more than once for 1 particular number and, as I had stated earlier, you cannot open the packets and remove some quantity of money from it. You have to use the packet as a whole. 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Tue May 04, 2010 1:18 pm  
 And the answer is, 1,2 (2^1),4 (2^2),8 (2^3),16 (2^4),32 (2^5),64 (2^6),128 (2^7),256 (2^ , 489( amount remaining ). 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Sat May 08, 2010 7:24 pm  
 The first mathematical puzzle I gave was solved by Pav. The second one by Choob. This is the third mathematical puzzle. As I always say, just think a bit and you will surely get the answer.
A group of 1000 people are invited by a host to a place with a huge corridor. One side of the corridor is just a plain wall. On the other wall, there are 1000 doors in a row, all of which open into small rooms. All the doors are numbered properly, in an order (1,2,3,4...1000) for the convinience of the guests. All the doors are initially closed. The host asks the thousand people to stand in a row, at the starting of the corridor. The first person is asked to open all the doors one by one. He does so. The second person is then asked to open every second door (2nd, 4th, 6th.....) if it is closed and close it if it is open ( In this case, he has to close every second door because the first person has aldready opened all the doors ). The third person is then asked to open every third door (3rd, 6th, 9th...) if it is closed and close it if it is open. The fourth one is asked to do the same with every fourth door. So on till the thousandth person.
My question now is, that after this whole exercise is done perfectly well, how many doors are open and how many doors are closed ? Also, tell me all the door numbers of the doors which are left open. 

 
Jammy Simply Sports Addict
Posts : 1549 Join date : 20100415 Age : 21 Location : Bury, England Birthday : 19951010
 Subject: Re: Puzzles and Questions Sat May 08, 2010 8:38 pm  
 Work it out yourself, lazyass 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Sat May 15, 2010 2:29 pm  
 Since no one has even made an attempt to try and solve this one, let me just give you the answer.
The only doors that remain open are perfect squares (1, 4, 9, 16, etc) because they are the only numbers divisible by an odd number of whole numbers; every factor other than the number's square root is paired up with another. Thus, doors will be changed an odd number of times, which means they will be left open.( The doors were initially closed ) All the other numbers are divisible by an even number of factors and will consequently end up closed.
So the number of open doors is the number of perfect squares less than or equal to one thousand. These numbers are one squared, two squared, three squared, four squared, and so on, up to thirty one squared. (Thirty two squared is greater than one thousand, and therefore out of range.) So the answer is thirty one. And, the doors numbers are :
1, 4, 9, 16, 25, 36, 49, 64 ...........................900, 961. 

 
Pav Administration
Posts : 4877 Join date : 20091205 Age : 24 Location : Australia Birthday : 19930315
 Subject: Re: Puzzles and Questions Sat May 15, 2010 2:56 pm  
 New one! I'll figure it out. _________________________________________________________________ 

 
Jammy Simply Sports Addict
Posts : 1549 Join date : 20100415 Age : 21 Location : Bury, England Birthday : 19951010
 
 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Sat May 15, 2010 3:41 pm  
 Sorry Pav. It has been a week since I posted it. Due to the lack of response, I inevitably had to post the answer.
Il definately find a new one for you Genius. 3 puzzles done. More coming soon... 

 
anurag_cheruvu Simply Sports Addict
Posts : 1169 Join date : 20100228 Age : 22 Location : India Birthday : 19950417
 Subject: Re: Puzzles and Questions Sun May 16, 2010 8:00 am  
 There are people at least trying to work these math puzzles out. One more now:
There once lived a man called Pav. One day, while sipping some tea, Pav was reminded of his dearest friend Choob, who he had not met for years. Pav decided that he he would travel all the way from Australia to England to meet Choob. The only problem was that Pav had no way of contacting Choob, since they had not been in touch for years together. Somehow, Pav gets to know that Choob lives in a town X. This town was primarily divided into two sectors. The first sector had houses numbered 120 and the second sector had houses numbered 2150. When Pav went to that town X, he spotted a passer by called Superhoops. Pav asked Superhoops if he knew where Choob lived. Superhoops then said : "Try to guess Choob's house number." Then, Pav asked Superhoops these three questions:
1) Does Choob live in the first sector or the second one ? 2) Is Choob's house number even ? 3) Is Choob's house number a perfect square ?
Hoops answers these questions. Then, Pav goes on to say : " I can guess Choob's house number if you tell me whether the digit 4 is in Choob's house number." After recieving an answer, Pav, in glee runs towards the house where he thinks Choob lives in. But to his surprise, a man called F1 Mania opens the door. A confused Pav tells F1 mania about Superhoops giving him all the clues as to where Choob lives. F1 bursts into laughter, and tells Pav that Superhoops was the biggest liar of the town and spoke nothing but lies. Pav thinks for a while, thanks F1, rings another doorbell. And this time, it is indeed Choob who opens the door. So finally, Pav found out where Choob lived.
In which house did Choob live ? And in which house did F1 mania live ? (House numbers) 

 
Sponsored content
 Subject: Re: Puzzles and Questions  
 

 
